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A list can represent an unordered mathematical set—simply consider a value
an element of a set if it appears in the list, and ignore the order of the
list. To form the union of two sets, use append
(as long as you
don't mind having duplicate elements). You can remove equal
duplicates using delete-dups
. Other useful functions for sets
include memq
and delq
, and their equal
versions,
member
and delete
.
Common Lisp note: Common Lisp has functions
union
(which avoids duplicate elements) andintersection
for set operations, but GNU Emacs Lisp does not have them. You can write them in Lisp if you wish.
This function tests to see whether object is a member of list.
If it is, memq
returns a list starting with the first occurrence of
object. Otherwise, it returns nil
. The letter ‘q’ in
memq
says that it uses eq
to compare object against the
elements of the list. For example:
(memq 'b '(a b c b a))
⇒ (b c b a)
(memq '(2) '((1) (2))) ; |
This function destructively removes all elements eq
to object
from list. The letter ‘q’ in delq
says that it uses
eq
to compare object against the elements of the list, like
memq
and remq
.
When delq
deletes elements from the front of the list, it does so
simply by advancing down the list and returning a sublist that starts after
those elements:
(delq 'a '(a b c)) ≡ (cdr '(a b c)) |
When an element to be deleted appears in the middle of the list, removing it involves changing the CDRs (voir la section Altering the CDR of a List).
(setq sample-list '(a b c (4))) ⇒ (a b c (4)) (delq 'a sample-list) ⇒ (b c (4)) sample-list ⇒ (a b c (4)) (delq 'c sample-list) ⇒ (a b (4)) sample-list ⇒ (a b (4)) |
Note that (delq 'c sample-list)
modifies sample-list
to splice
out the third element, but (delq 'a sample-list)
does not splice
anything—it just returns a shorter list. Don't assume that a variable
which formerly held the argument list now has fewer elements, or that
it still holds the original list! Instead, save the result of delq
and use that. Most often we store the result back into the variable that
held the original list:
(setq flowers (delq 'rose flowers)) |
In the following example, the (4)
that delq
attempts to match
and the (4)
in the sample-list
are not eq
:
(delq '(4) sample-list) ⇒ (a c (4)) If you want to delete elements that are |
This function returns a copy of list, with all elements removed which
are eq
to object. The letter ‘q’ in remq
says that
it uses eq
to compare object against the elements of
list
.
(setq sample-list '(a b c a b c)) ⇒ (a b c a b c) (remq 'a sample-list) ⇒ (b c b c) sample-list ⇒ (a b c a b c) |
The function memql
tests to see whether object is a member of
list, comparing members with object using eql
, so
floating point elements are compared by value. If object is a member,
memql
returns a list starting with its first occurrence in
list. Otherwise, it returns nil
.
Compare this with memq
:
(memql 1.2 '(1.1 1.2 1.3)) ; |
The following three functions are like memq
, delq
and
remq
, but use equal
rather than eq
to compare
elements. Voir la section Equality Predicates.
The function member
tests to see whether object is a member of
list, comparing members with object using equal
. If
object is a member, member
returns a list starting with its
first occurrence in list. Otherwise, it returns nil
.
Compare this with memq
:
(member '(2) '((1) (2))) ; |
If sequence
is a list, this function destructively removes all
elements equal
to object from sequence. For lists,
delete
is to delq
as member
is to memq
: it uses
equal
to compare elements with object, like member
; when
it finds an element that matches, it cuts the element out just as
delq
would.
If sequence
is a vector or string, delete
returns a copy of
sequence
with all elements equal
to object
removed.
For example:
(setq l '((2) (1) (2))) (delete '(2) l) ⇒ ((1)) l ⇒ ((2) (1)) ;; If you want to change |
This function is the non-destructive counterpart of delete
. It
returns a copy of sequence
, a list, vector, or string, with elements
equal
to object
removed. For example:
(remove '(2) '((2) (1) (2))) ⇒ ((1)) (remove '(2) [(2) (1) (2)]) ⇒ [(1)] |
Common Lisp note: The functions
member
,delete
andremove
in GNU Emacs Lisp are derived from Maclisp, not Common Lisp. The Common Lisp versions do not useequal
to compare elements.
This function is like member
, except that object should be a
string and that it ignores differences in letter-case and text
representation: upper-case and lower-case letters are treated as equal, and
unibyte strings are converted to multibyte prior to comparison.
This function destructively removes all equal
duplicates from
list, stores the result in list and returns it. Of several
equal
occurrences of an element in list, delete-dups
keeps the first one.
See also the function add-to-list
, in Modifying List Variables, for a way
to add an element to a list stored in a variable and used as a set.
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Ce document a été généré par Eric Reinbold le 13 Octobre 2007 en utilisant texi2html 1.78.